(-1/12)x^2+2x+3=0

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Solution for (-1/12)x^2+2x+3=0 equation: 


x in (-oo:+oo)

(-1/12)*x^2+2*x+3 = 0

2*x-1/12*x^2+3 = 0

DELTA = 2^2-(-1/12*3*4)

DELTA = 5

DELTA > 0

x = (5^(1/2)-2)/(-1/12*2) or x = (-5^(1/2)-2)/(-1/12*2)

x = -6*(5^(1/2)-2) or x = 6*(5^(1/2)+2)

x in { -6*(5^(1/2)-2), 6*(5^(1/2)+2) }

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